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Next: Density of States Per Up: Lecture 2 Previous: Seebeck Effect - Thermopower

Quantum Theory of Electrons in Metals

(``Free Electrons; Sommerfeld")

(AM, Ch 2)

Now let's put $ QM$ into the model.

The most important effect of putting quantum mechanics into the theory of metals is the result of treating electrons as fermions with Fermi-Dirac statistics, rather than as a classical gas of particles obeying the Kinetic Theory of Gases. But let's start at the beginning.

When electrons are treated quantum mechanically, 2 things change: (a) possible states are quantized; (b) particles are indistinguishable.

=2.0 true in \epsfbox{squarePotential.eps}
Consider non-interacting electrons moving (freely) in a constant potential which we take to be zero. Schroedinger's equation in 1D is
$\displaystyle \frac{\hbar^2}{2m}\frac{d^2\psi_n}{d x^2} = \varepsilon _n\psi_n$      

What boundary conditions do we use? (It doesn't matter all that much because the bulk properties aren't really affected by what goes on at the surface.)
(a)
Realistic, i.e., $ \psi_n$ finite outside the metal but decaying exponentially $ (\to 0$ as $ x \to \infty$). This is practically never used for bulk calculations since $ r_{decay} \sim$ atomic dimensions.
(b)
Box: Standing Wave Solutions $ \qquad\qquad \psi_n = 0$ at walls
$ \psi_n(x) = \sqrt{\frac{\textstyle 2}{\textstyle L}} \sin \left( \frac{\textst...
...arepsilon _n = \frac{\textstyle n^2\pi^2\hbar^2}{\textstyle 2mL^2}
\quad n > 0$.
We're interested in transport - want traveling waves.
(c)
Periodic: $ \psi_n(x+L) = \psi_n(x)$
Now traveling wave solutions are allowed.
    $\displaystyle \psi_n(x) = \sqrt{\frac{1}{L}} e^{ik_nx}$  
    $\displaystyle k_n = \frac{2n\pi}{L} \quad n \gtrless 0$  
    $\displaystyle E_n = \frac{\hbar^2k^2_n}{2m} = \frac{\hbar^2}{2m} \left(
\frac{2n\pi}{L} \right)^2$  

It is easy to generalize this to 3D. Consider a box with sides $ L_x,
L_y, L_z$: Schroedinger's equation becomes

$\displaystyle - \frac{\hbar^2}{2m} \nabla^2 \psi_n = - \frac{\hbar^2}{2m} \left...
...rtial y^2}+\frac{\partial ^2\psi_n}{\partial z^2}\right) = \varepsilon _n\psi_n$      

For periodic b.c.'s, the solution is a product wavefunction
$\displaystyle \psi_n(x,y,z)$ $\displaystyle =$ $\displaystyle \frac{1}{\sqrt{V}} (\exp  ik_xx) (\exp  
ik_yy)(\exp ik_zz)$  
  $\displaystyle =$ $\displaystyle \frac{1}{\sqrt{V}} e^{i\vec{k}\cdot\vec{r}}$  
$\displaystyle E_n$ $\displaystyle =$ $\displaystyle \frac{\hbar^2k^2}{2m}$  

with
$\displaystyle k_x = \frac{2n_x\pi}{L_x} \qquad k_y = \frac{2n_y\pi}{L_y} \qquad k_z
= \frac{2n_z\pi}{L_z}$      

The momentum carried in the plane wave state is $ \vec{p} =
\hbar\vec{k}$ and the velocity $ \vec{v} = \frac{\textstyle \hbar\vec{k}}{\textstyle
m}$. Each state is characterized by $ \vec{k}$ and by the spin $ \sigma$ along some chosen axis. There are 2 different states for each allowed value of $ \vec{k}$. Note that the probability density $ \vert\psi_n(\vec{r})\vert^2$ is uniform in space.

Density of States

Suppose we are interested in some property of the one-electron states, such as the total average number of electrons in them. We sum over the states

    $\displaystyle N = \sum\limits_{\vec{k}\sigma} n_{k\sigma}\qquad   {\mbox{ sum
...
...{k}'s \atop \textstyle k_x = \frac{\textstyle 2n\pi}{\textstyle L}, {\rm etc.}}$  

where $ n_{k\sigma}$ is the number of electrons in state $ k$ with spin $ \sigma$. Assume that $ n_{k\sigma}$ is a rather smoothly varying function of $ \vec{k}$. This allows us to transform the sum into an integral.
$\displaystyle \sum\limits_{\vec{k}\sigma} n_{k\sigma} \to \sum\limits_{\sigma}\int
d^3k\; n_{k\sigma}   \varphi (\vec{k})$      

$ \varphi (\vec{k})$ is the density of states per unit volume of $ \vec{k}$-space. What is $ \varphi (\vec{k})$? $ k_x = \frac{\textstyle 2n\pi}{\textstyle
L_x}$ implies that the density of allowed $ k_x$ values along the $ k_x$-axis is $ \frac{1}{2\pi/L_x} = \frac{L_x}{2\pi}$. Similar arguments for $ k_y$ and $ k_z$ lead to
\fbox{$
\textstyle \varphi (\vec{k}) = \frac{\textstyle L_xL_yL_z}{\textstyle (2...
...V}{\textstyle (2\pi )^3} = \mbox{ density of states of one spin in
$k$-space}$}
Note that this is independent of the ratio of $ L_x, L_y$, and $ L_z$. In fact, $ \varphi (\vec{k})$ is independent of the sample shape in the limit $ V \to \infty$, except for the lowest few states.

If spin is included, put in an extra factor of 2. Thus

$\displaystyle \sum\limits_{\vec{k}\sigma}   n_{k\sigma} \longrightarrow
\sum\l...
... \int \frac{d^3k}{(2\pi )^3} n_{k\sigma} =
\frac{2V}{(2\pi )^3} \int d^3k  n_k$      

if $ n_{k\sigma}$ is independent of $ \sigma$. In general for any dimension $ d$
$\displaystyle \sum\limits_{\vec{k}\sigma} \longrightarrow \frac{2V_d}{(2\pi )^d} \int d^dk$      

where $ V_d$ is the $ d$-dimensional volume.
next up previous
Next: Density of States Per Up: Lecture 2 Previous: Seebeck Effect - Thermopower
Clare Yu 2006-10-03