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LECTURE 4
Blackbody Radiation
Blackbody radiation is a nice example of the statistical mechanics that
we have been discussing. A black body is a perfect absorber and absorbs
all the radiation incident on it. If its temperature is kept constant,
then the amount of power it radiates must equal the amount of power
it absorbs. Otherwise it would heat up or cool off. We can imagine
the black body being kept inside some kind of closed container which
is at the same temperature T. The radiation field inside this enclosure
is in equilibrium. In other words there is a gas of photons in thermal
equilibrium inside the enclosure. By thermal equilibrium, we mean that
the average occupation number <ns> of the single particle states is
given by the Planck distribution that we talked about in lecture 3.
One can imagine making
a histogram by counting the photon energy density in each frequency range
from to
.
It turns out that this distribution of the energy
density of blackbody radiation is
a universal curve that depends only on the temperature T. In other
words if one plots the distribution of the photon energy density
(counting both directions of polarization) as a function of
photon (angular) frequency
, the shape of the curve is universal and the position of
the peak is a function only of the temperature.
When we say that the curve is universal, we mean that it doesn't
depend on the size or shape of the box, or what the walls are made of.
All that matters is the temperature.
Blackbody radiation is historically important in physics for
two reasons. The first is that the measurement of the spectral
distribution in the late 1800's led Planck to come up with the
idea of energy quantization. He couldn't explain the distribution
unless he postulated that . This marked the birth of quantum
mechanics. The second reason that blackbody radiation is important is
that 3 K black body radiation pervades the universe and is the
remnant of the Big Bang. This radiation is in the microwave region.
We will come back to this at the end of the
course.
Let's calculate the distribution of the mean energy density of
blackbody radiation. Since the size and shape of the box don't matter,
let's imagine a rectangular box of volume V filled
with a gas of photons that are in
thermal equilibrium. The box has edges with lengths Lx,
Ly, and Lz such that each of these lengths is much larger
than the longest wavelength of significance.
There are 2 factors that determine the energy
density at a given frequency. The first is the average energy in
each state s which is given by
If we set
and
,
we can rewrite this to give:
The second factor is the number of states per unit volume
whose frequency lies in
the range between and
. We figured this out
at the end of lecture 1. We found that
So at temperature T the mean energy density
contained in the photon gas by photons whose
frequencies are between and
is given
by the product of the average energy in each single photon state
and the density of states which lie in this frequency range:
We can rewrite this to give:
This is Planck's law for the blackbody spectrum.
blackbody.eps
We can take the high temperature limit to get the classical limit of this
spectrum. In the high temperature limit, is small so we can
expand the exponential in the denominator:
So the high temperature limit of (6) is
or, using
, we can write
This is the Rayleigh-Jeans formula for blackbody radiation. Notice that
eqn. (9) increases as
. Therefore the classical spectrum (9)
predicts that the energy density goes to infinity as the frequency goes
to infinity. By the end of the 1800's the black body spectrum had
been measured and the classical formula had been calculated. There was
a clear lack of agreement, so people knew they had a problem. Planck
resolved the conflict by proposing that electromagnetic
energy was not continuous, but rather was quantized. He proposed
(or ) and derived Planck's law (6).
This fit the data very well, and quantum mechanics was born.
We can rewrite (6) in terms of a dimensionless parameter
:
Planck's law becomes:
If we plot
versus , the maximum occurs around
.
scaledbb.eps
So if at temperature T1 the maximum
occurs at frequency
, then at some other temperature
T2 the maximum occurs at
. This is because
or
This is called the Wien displacement law. It says that
This was initially an empirical relation that was deduced from the
experimental data. We see that it also follows from Planck's law.
It is often useful in physics to express things in terms of
dimensionless parameters. The Wien displacement law is an example
of useful scaling relations that can result from this.
We can also calculate the total energy density RT contained in
the photon gas at temperature T by integrating (6) over
frequency:
Using (11), we can rewrite this as
One can evaluate the integral exactly. The answer is
Using this, one finds
This is known as the Stefan-Boltzmann law. The important point is
that the total energy density goes as the fourth power of the temperature:
Finally the mean pressure <p> exerted on the walls of the
enclosure by the radiation is simply related to the total energy
density:
(The pressure can also be written as
.)
The ``3'' in the denominator reflects the fact that the box is 3 dimensional.
Radiation pressure is quite small, but it is what gives comets their tails.
Solar radiation is what pushes tiny bits of dust
and ice that come from the ice ball away from the sun and produces
the tail. The comet tail always points away from the sun. We will
see examples later where a microscopic understanding of radiation
pressure leads to laser cooling of beams of atoms.
Atomic Orbitals
It's always a good idea to have some idea of how big things are so
you can easily estimate what's important at a particular energy or
length scale. Visible light consists of radiation with wavelengths
in the range of 4000 Å(violet) to 7500 Å(red). When ordinary
white light passes through a prism, it breaks up into a continuous
rainbow spectrum. But if you take a bead of sodium, for example,
and put it in a flame, it will give off yellow light. If you pass this
light through a prism, you get a spectrum of distinct lines, not
a continuous spectrum. Each line represents a definite wavelength or energy.
Each element has its own characteristic line spectrum; it's like
a fingerprint. These lines are a result of the fact that energy
levels in atoms are quantized. So electrons
in the sodium atoms get excited into higher energy levels by the flame.
When these excited electrons make transitions to lower energy levels
they emit photons in order to conserve energy. These photons produce the
line spectrum. A famous set of lines is the Balmer series which is
emitted by hydrogen in the visible region of the spectrum. It was
found empirically that the frequencies of these lines can be expressed
by the formula
where n is an integer equal to, or greater than, 3.
To explain the Balmer series Bohr proposed that the electron of hydrogen
can exist only in certain spherical orbits (called energy levels or shells),
which are arranged concentrically around the nucleus. These orbits
are subject to a quantum restriction: the orbital angular momentum is
quantized in units of :
where n= 1, 2, 3 ... Here m is the mass of the electron, v is its
velocity, and r is the radius of the orbit. Each orbit has a characteristic
energy. As long as the electron remains in a given orbit, it neither
absorbs nor radiates energy.
Thus, the K level (n=1), the shell closest to the nucleus, has the
smallest radius and lowest energy. The next shell (L; n=2) has a larger
radius and a higher energy. The shells are labelled K (n=1),
L (n=2), M (n=3), N (n=4), and O (n=5), in order of increasing
radius from the nucleus.
We can deduce the energy of the different n levels using Bohr's
postulate in the following way. Setting the centripetal force equal
to the Coulomb force on an electron from the nucleus, we obtain:
where Z is the number of protons in the nucleus. Z is called the
atomic number. We can rewrite this:
Now we use Bohr's quantization condition:
Squaring (26) and inserting this into (24), we get
or
If we solve this for the smallest orbit (n=1) of hydrogen
(Z=1), we get the Bohr radius ro:
Numerically
ro=0.529 Å. This is a good number to remember since
it is a characteristic atomic size.
The total energy of the electron is the sum of its kinetic plus its
potential energy:
Using (23), we have
Therefore,
Substituting in (28), we get
Here we see that the quantization of momentum leads to the
quantization of the energy of the Bohr orbits.
When the electrons are arranged as close as possible to the nucleus
(in the case of hydrogen, one electron in the K level), they are
in the lowest energy state which is called the ground state. When
an atom absorbs energy, one or more of the electrons can jump to
higher energy levels, leaving the atom in an excited state.
When an electron falls back to a lower orbit, it emits an definite
amount of energy equal to the difference in energy between the
two levels. Let Eo denote the energy of the initial outer level and
Ei be the energy of the final inner level. This energy is emitted
as a photon with a characteristic energy. The energy of the photon is
Substituting in En from (33), we get
or
If we evaluate this expression for hydrogen with Z=1, the
frequencies of photons emitted by transitions from higher levels
n to the n=2 level leads to the Balmer series formula
Photons emitted due to electronic transitions to the n=1 level are
in the ultraviolet region. These transitions give rise to the Lyman
series. The lines associated with having an n=3 final state are
in the infrared and are called the Paschen series.
If an electron is removed to an infinite shell, the atom is said
to be ionized; the ionization energy is the minimum amount of energy
required for this process.
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Clare Yu
2002-10-09