LECTURE 17
Ferromagnetism
(Refs.: Sections 10.6-10.7 of Reif; Book by J. S. Smart, Effective Field Theories of Magnetism)

Consider a solid consisting of N identical atoms arranged in a regular lattice. Each atom has a net electronic spin S and a magnetic moment ⃗μ that is related to the spin by

⃗μ =  gμoS
(1)

where g is the g-factor and μo is the Bohr magneton. In the presence of an externally applied magnetic field Ho along the z direction, the Hamiltonian Ho is given by

            N                     N
H   = - gμ  ∑  S  ⋅ H =  - gμ H  ∑  S
  o        oj=1 j    o       o  oj=1  jz
(2)

In addition, each atom can interact with its neighbors. In the past we ignored interactions and assumed that the spins were noninteracting. This is ok as long as kBT the interaction energy. In this case, well-localized spins should obey Curie’s law, χ ~ 1∕T, far from saturation and the magnetization M should vanish as Ho 0. This is how a paramagnet behaves.

However, if the interaction between spins >~kBT, magnetic ordering may occur. We can think of this as being due to an effective magnetic field produced at a given site by its neighbors. For example, suppose a given electron is . If it produces a field at a neighboring site parallel to itself, then the neighbor will also tend to be polarized : in fact, we would expect all spins or all spins in the ground state. This is a ferromagnet – it has “spontaneous magnetization” even when Ho = 0. Ferromagnets are bar magnets and stick to your refrigerator door. If, on the other hand, the field produced is antiparallel to the spin, we expect to get ↑↓↑↓ .... This is an antiferromagnet and has zero net magnetization.

All forms of magnetic ordering disappear as the substance is heated: typical transition temperatures are of order 100 to 1000 K. The temperature at which the spontaneous magnetization disappears is called the Curie temperature (TC) for a ferromagnet. The ordering temperature for an antiferromagnet (AF) is called the Néel temperature (TN).

Origin of the Ordering Field: Our first guess of the dominant magnetic interactions would be magnetic dipole-dipole interactions. But the strength of nearest neighbor dipole-dipole interactions is of order 1 K which is much smaller than the transition temperature (TC) for a ferromagnet. (See Reif page 429 for more details of this estimate.) So dipolar interactions cannot account for magnetic ordering.

The origin of the ordering field is a quantum mechanical exchange effect. The derivation is given in the appendix and you will see it in the second quarter of quantum mechanics. Let me try to explain the physics behind the exchange effect. Basically the Coulomb interaction between two spins depends on whether the spins form a singlet or a triplet. A triplet state is antisymmetric in real space while the singlet state has a symmetric wavefunction in real space. So the electrons stay out of each others way more when they are in the triplet state. As a result, the Coulomb interaction between two electrons is less when they are in a triplet state than when they are in a singlet state. So the interaction energy depends on the relative orientations of the spins. This can be generalized so the spins don’t have to belong to electrons and the spins need not be spin-1/2. This interaction between spins is called the exchange interaction and the Hamiltonian can be written as

        ∑
H =  - 2   JijSi ⋅ Sj
        i>j
(3)

This is known as the Heisenberg Hamiltonian. We put i > j in the sum to prevent double counting. Jij is called an exchange constant. Since it depends on the overlap of wavefunctions, it falls off rapidly as the distance between the spins increases. Often Jij is taken to be non-zero only between nearest neighbor spins. If we take Jij = J, then

          ∑
H  = - 2J    Si ⋅ Sj
          i>j
(4)

Notice that if J > 0, then the spins lower their energy by aligning parallel to each other. If J < 0, the spins are anti-parallel in their lowest energy spin configuration. (In a spin glass, Jij is a random number that is different for each pair i and j.)

The spins need not have S = 12. For example, if there is both spin and orbital angular momentum (S and L), then Ji = Li + Si is the relevant “spin” vector. Ji is the total angular momentum of the ith atom.

A simpler Hamiltonian can be obtained by just considering the z components of the spins. This is called the Ising model.

         ∑
H =  - 2J   SizSjz
         i>j
(5)

For S = 12, Sz can take only 2 values: +1/2 or -12.

Magnetic systems are not only important in their own right, but also because they are simple examples of interacting systems and can represent other types of systems, e.g., a system of neurons.

Weiss Mean Field (or Molecular Field) Theory of Ferromagnetism

This is a prototype for mean field theories and second order phase transitions. In 1907 Pierre Weiss proposed an effective field approximation in which he considered only one magnetic atom and replaced its interaction with the remainder of the crystal by an effective magnetic field Heff. We can extract the single atom Hamiltonian from the Heisenberg Hamiltonian:

            ∑
H1 = - 2Si ⋅   JijSj
             j
(6)

We now wish to replace the interactions with other spins by an effective magnetic field Heff so that H1 has the form

H1  = - ⃗μi ⋅ Heff = - gμBSi ⋅ Heff
(7)

where

        -2--∑
Heff =  gμB    JijSj
             j
(8)

In the spirit of the Weiss approximation, we then assume that each Sj can be replaced by its average value Sj= S

             (      )
H    =  2⟨S⟩-(∑   J )
  eff   gμB    j   ij
(9)

By assumption, all magnetic atoms are identical and equivalent. This implies that Sis related to the magnetization of the crystal by

M  = ng μ  ⟨S⟩
         B
(10)

where n is the number of spins per unit volume.

                  (      )
             2     ∑
Heff   =   --2--2-(   Jij) M
           ng μ B   j
       =   λM                                         (11)
where λ is the Weiss molecular field coefficient:
           (      )
       2     ∑
λ = ng2-μ2-(    Jij)
         B    j
(12)

If there are only nearest-neighbor interactions, jJij = zJ where z is the number of nearest neighbors, i.e., the coordination number. Then

      2zJ
λ =  --2--2-
     ng μ B
(13)

If there is an external field Hext, then the total field acting on the ith spin is

H  = Heff  + Hext
(14)

Since M is a paramagnetic function of H:

M  = f (Heff + Hext)
(15)

where

Heff  = λM
(16)

We can solve these two equations self-consistently for M. Let’s do some simple examples of this.

  1. Suppose that Hext is small, and let us assume that M and hence Heff will also be small. Then assuming that M Hext Heff
    M   =   χC H            where χC  = Curie susceptibility
    =   χ  (H    + H    )
         C    ext    eff
    =   χC Hext + χCλM                                             (17 )
    Solving for M yields
    M   = ---χC---H
      1 - λχC   ext
    (18)

    Since χ = ∂M∕∂Hext, we get

    χ =  --χC----
     1 - λχC
    (19)

    Putting χC = C∕T, where C is the Curie constant, gives the Curie-Weiss Law:

    χ (T) = ---C---- = ---C----
        T -  λC    T -  TC
    (20)

    where TC = λC. This reduces to the Curie law χ~=C∕T for T TC, but as we approach TC from above, the susceptibility diverges. This indicates that at the transition temperature (T = TC), the system can acquire a spontaneous magnetization even in the absence of an external field, i.e., it becomes ferromagnetic. If we plug in our expressions for λ and C:

             2zJ
λ   =   --2-2--
        ng μB
        n(gμB-)2S-(S-+-1)-
C   =         3k                                    (21 )
                 B
    (The expression for C is from Reif Eq. (7.8.22). We will derive it later in this lecture.) We obtain
                2zJ S(S +  1)
TC  = λC  = -------------
                 3kB
    (22)

    where TC is the Curie temperature. This is reasonable since the energy of a given spin S in the field of its neighbors is ~ zJS2. Notice that T C is proportional to the exhange energy J and to the number of neighbors z.

  2. Below TC, or in high fields above TC, we can no longer use the Curie approximation M = χCH. Rather we must use the full nonlinear expression which leads to the Brillouin function. (For S = 12, Brillouin function reduces to tanh.) The one-atom Hamiltonian is (again assuming that Hext, Heff, and M to be along the z-axis)
    H1 =  - gμBSzH        H  =  Hext + Heff
    (23)

    and has eigenvalues

    Em  = - gμBmH          m =  S,S - 1, ...,- S
    (24)

    The partition function is

           ∑
Z   =      e-Em∕kBT
        m
         S∑
    =        egμBmH ∕kBT
       m= -S
         S∑
    =        emx∕S       x = g-μBSH-- (dimensionless)
       m= -S                   kBT
            (2S+1  )
        sinh--(2S--x)--
    =    sinh  -1 x                                                (25 )
              2S
    The magnetization is
    M    =  n ⟨μz ⟩

     =  ng μB⟨Sz ⟩
        ng μB ∑Sm= -S me -Em∕kBT
     =  -------------------------
                  Z (x)
        ng-μB- ∑S      mx∕S
     =    Z         me
              m= -S
               ∂-ln-Z-
     =  ng μBS   ∂x                                     (26 )
    Using ln Z = ln [    (2S+1  )]
 sinh   2S  x- ln [     ( x-)]
 sinh  2S, we get
    M   = ngμBSBS  (x )
    (27)

    where the Brillouin function

             2S +  1     ( 2S + 1  )    1      ( x )
BS (x) = -------coth   ------x   - ---coth   ---
           2S            2S        2S        2S
    (28)

    For S = 12,

    B    (x ) = tanh x
  1∕2
    (29)

    If we define a dimensionless field h = BH∕kBT, then

    M  = ng μBSBS  (hS)
    (30)

    Aside: Let us take a moment to derive the expression for the Curie constant C in Eq. (21). At high temperatures or small fields, hS 1. For x 1

              S-+-1-
BS (x) ≈   3S  x       for x ≪ 1
    (31)

    Plugging this into Eq. (30) yields

          1
M  =  -ng μBhS (S +  1)
      3
    (32)

    Plugging in h = BH∕kBT gives

            ng2μ2BS-(S-+-1)
M   =        3kBT      H
    =   χ  H                                        (33 )
         C
    where
                                   2
χC =  C-     and  C  = n-(gμB-)-S-(S-+--1)
      T                       3kB
    (34)

    This is where Eq. (21) came from.

    Now back to mean field theory. Eq. (30) is a self-consistent equation for M because H = Hext + λM. To solve for M, some numerical or graphical method of solution must be employed. The graphical procedure of Weiss is probably the simplest method. To use this, rewrite the equation for M in terms of a reduced magnetization σ:

           M
σ =  ------- = BS (hS )
     ng μBS
    (35)

    For S = 12,

    σ = tanh (hS)
    (36)

    This gives one curve. The other curve comes from

                              g μBS
 hS   =   hextS +  heffS = ------(Hext + Heff )
                           kBT             (            )
                             2zJ-                -2zJ---
Heff  =   λM  = λng μBS σ =  gμB S σ         λ = ng2 μ2B
                            2
 hS   =   gμBS--Hext + 2zJS--σ
           kBT          kBT
           kBT         gμB
   σ  =   -----2hS  - ------Hext
          2zJ S       2zJ S
      =   D ⋅ hS + A                                                (37 )
    This gives a straight line for σ versus hS. The intersection gives a self-consistent solution for σ and hence M.

    brillouin1.eps

    The most important result of the Weiss theory is that when Hext = 0 and the straight line passes through the origin, there is still a non-zero solution for σ, i.e., a spontaneous magnetization is predicted. The general behavior of the spontaneous magnetization can be inferred without extensive calculations. The slope of the straight line is proportional to T (D T), and rotating the line about the origin corresponds to changing the temperature. When T 0, σ 1, and the material becomes completely magnetized. As T is increased, the spontaneous magnetization is reduced and finally vanishes when the slope of the line is equal to the initial slope of the Brillouin function. This occurs at the Curie temperature TC that we found earlier.

    spontaneousM.eps

    We can solve for TC by matching the slopes at x = 0 of the Brillouin function and the straight line:

              S + 1
BS (x) ≈  -----x       for x ≪ 1
           3S
    (38)

    The straight line at small x is given by

                         kBT
BS (x = hS ) = σ =  -----2x       if Hext = 0 and x = hS
                    2zJS
    (39)

    Matching the slopes at T = TC yields

    -kBTC--  =  S-+--1
2zJ S2        3S
            2zJ S (S +  1)
    TC   =  -------------                           (40 )
                 3kB
    which is what we got before. We can use this to write a special equation of state for the spontaneous magnetization. For Hext = 0,
        -kBT---
σ = 2zJ S2 hS
    (41)

    Solving for hS yields

                  2
hS   =   2zJ-S-σ-
           kBT
           3S   TC
     =   (S-+-1)-T-σ                              (42 )
    So at Hext = 0, σ = BS(hS) becomes
            (        )
σ =  BS   -3S---σ-
          S + 1 τ
    (43)

    where τ = T∕TC.

    Temperature dependence of the magnetization:

    T ~ 0 Mean field theory predicts

             1     (    3   TC )
σ ≃  1 - --exp  - ---------  + ...
         S        S + 1 T
    (44)

    Experiment is closer to spin wave theory:

                3∕2
σ = 1 - AT     - ...
    (45)

    For T ~ TC-

        (        )1∕2
σ ~   TC---T--
        TC
    (46)

    from mean field theory. In general one writes

              (        )
           TC----T- β
M  ~ σ ~      T
               C
    (47)

    where β is a critical exponent. Experiment finds β ~ 13.

OP.eps

Appendix: Derivation of Quantum Mechanical Exchange
The origin of the ordering field is a quantum mechanical exchange effect. The simplest example of the exchange effect can be seen in the quantum mechanics of a system of 2 electrons. The Hamiltonian for the pair is
                  2           2
H  = H1  + H2 +  e--=  Ho + -e-
                 r12        r12
(48)

where r12 = |r1 - r2|, and H1 and H2 are the Hamiltonians of electron 1 and electron 2, respectively. The electrons are either in a singlet state or a triplet state:

ψS  =   √1--[ϕi(1)ϕj(2) + ϕi(2)ϕj(1)]χo
          2
        -1--
ψT  =   √ --[ϕi(1)ϕj(2) - ϕi(2)ϕj(1)]χ1                    (49)
          2
where the singlet spin wavefunction (S = 0) is
χ  = √1--[↑↓ - ↓↑]
 o     2
(50)

and the triplet spin wavefunction (S = 1) is

     (
     |{  ↑↑           Sz = 1
χ1 =    1√-[↑↓ + ↓↑]  Sz = 0
     |(  ↓2↓           S  = - 1
                      z
(51)

Without the Coulomb interaction, the singlet and triplet are degenerate (have equal energy):

           o
HoψT,S =  ET,SψT,S
(52)

where ET o = E So = E i + Ej. If we include the Coulomb interaction e2∕r 12 using first order perturbation theory, then

           o        e2-          o
 ES  =   E  + ⟨ψS | r   | ψS⟩ = E  + Cij + Jij                 (53)
                     122
E    =   Eo + ⟨ψ   | e- | ψ ⟩ = Eo + C  -  J                  (54)
  T              T  r12   T            ij    ij
where
         ∫   *    *   e2            3
Cij  =     ϕ i(1)ϕ j(2 )---ϕi(1 )ϕj (2 )d r + (i ↔ j )               (55)
         ∫            r122
             *    *   e--           3
 Jij =     ϕ i(1)ϕ j(2 )r12 ϕi(2 )ϕj (1 )d r + (i ↔ j )               (56)
Cij is the average Coulomb interaction between 2 electrons in states i and j. Jij is the exchange energy of 2 electrons in states i and j. Thus the singlet and triplet energies are now different; whether the singlet state or the triplet state has the lower energy and is the ground state depends on the sign of Jij. In this particular case, Jij is positive and the triplet has lower energy because the antisymmetric spatial wavefunction weakens the Coulomb repulsion. In more general cases, e2∕r 12 is replaced by V (r1,r2), and Jij can be either positive or negative.

The exchange energy can be rewritten in terms of a spin exchange operator

  σ   1-
P   = 2 (1 + ⃗σ1 ⋅⃗σ2)
(57)

which has the property

P σχms (τ ,τ ) = χms (τ ,τ )
     S   1  2     S    2  1
(58)

where χSms(τ1,τ2) is the spin wavefunction of 2 particles with spin coordinates τ1 and τ2. To prove this, note that for S = S1 + S2

    S2  =   S21 + S22 + 2S1 ⋅ S2                       (59)
            1 [            ]
S1 ⋅ S2 =   -- S2 - S21 - S22                          (60)
            2
Since S = ⃗σ2 and S1 = S2 = 12, S12 = S 1(S1 + 1) = 34. So
               [             ]
1-           1-             3-
4⃗σ1 ⋅⃗σ2  =   2  S(S +  1) - 2
              [             ]   {
 ⃗σ1 ⋅⃗σ2  =   2 S (S + 1) - 3- =    - 3  for S =  0               (61)
                           2       1    for S =  1
So
  σ ms              1              ms
P  χS=1 (τ1,τ2)  =  2-[1 + ⃗σ1 ⋅⃗σ2 ]χS=1 (τ1,τ2)
                      ms
                 =  χ 1 (τ1,τ2)
                 =  χms1 (τ2,τ1)                               (62)
and
  σ ms=0             1        ms=0
P  χS=0  (τ1,τ2) =   2-[1 - 3]χS=0  (τ1,τ2)
                        0
                 =   - χ0(τ1,τ2)
                 =   χ00 (τ2,τ1)                              (63)
Therefore,
P σχms (τ ,τ ) = χms (τ ,τ )
     S   1  2     S    2  1
(64)

Thus we can write

         o              m     σ   m
E   =   E  + Cij - Jij⟨χ Ss | P | χSs⟩
         o            [1              ]
    =   E  + Cij - Jij --(1 + ⟨⃗σ1 ⋅⃗σ2⟩)
        {              2
    =     ES   if S = 0                                    (65)
          ET   if S = 1
This implies that we can write the Hamiltonian in the form
             1
H  = const - --Jij⃗σ1 ⋅⃗σ2
             2
(66)

We now make a rather bold leap of faith and assume that we can write a similar Hamiltonian for a system with many electrons.

         ∑
H =  - 1-   Jij⃗σi ⋅⃗σj
       2 i>j
(67)

This is the Heisenberg Hamiltonian and Jij are called the exchange constants. Usually one writes

        ∑
H =  - 2   JijSi ⋅ Sj
        i>j
(68)

where the factor of 4 is from (S = σ∕2)2.